Отправлено Mik 21 августа 2002 г. 17:49 В ответ на: Хе-хе отправлено Oldring 21 августа 2002 г. 11:57

Вот это из K&R, 2nd edition:

When a macro has been defined in the second form, subsequent textual instances of the macro identifier followed by optional white space, and then by (, a sequence of tokens separated by commas, and a ) constitute a call of the macro. The arguments of the call are the comma-separated token sequences; commas that are quoted or protected by nested parentheses do not separate arguments. During collection, arguments are not macro-expanded. The number of arguments in the call must match the number of parameters in the definition. After the arguments are isolated, leading and trailing white space is removed from them. Then the token sequence resulting from each argument is substituted for each unquoted occurrence of the corresponding parameter's identifier in the replacement token sequence of the macro. Unless the parameter in the replacement sequence is preceded by #, or preceded or followed by ##, the argument tokens are examined for macro calls, and expanded as necessary, just before insertion.

Вроде всё понятно, для компилятора ANSI C это ошибка при вызове макроса (неправильное число аргументов).

• В С++ точно также, только ошибки никакой нет. — Oldring   (21.08.2002 18:01, 347 байт)