<pre>
Below is a C program that you can compile and run on your WIN2K machine. The program will
give you a rough idea of how much memory your machine will allow for a given
process. [NOTE: You can use this C program on LINUX/SOLARIS/HPPA as well.]


#include <stdlib.h>
#include <malloc.h>
#include <stdio.h>

#define KBYTE 1024
#define MBYTE (KBYTE*1024)
#define GBYTE (MBYTE*1024)
#define CHUNK 32*KBYTE


void main(int argc, char **argv){
long chunks = 0;
void *pmem;
int nelem=1;
int index=0;

printf("\n***Allocating all available memory\n");
printf("***Allocating 1 32K element at a time\n");

while (pmem=calloc(nelem,(size_t)CHUNK)){
chunks = chunks + nelem;
switch(chunks){
case 10: {
printf("***Increasing to 2 32K elements per allocation\n");
nelem = 2;
break;
}
case 32: printf("... 1 MB\n"); break;
case 40: {
nelem = 4;
printf("***Increasing to 4 32K elements per allocation\n");
break;
}
case 320: printf("... 10MB\n"); break;
case 3200: printf("... 100MB\n"); break;
case 8192: printf("... 256MB\n"); break;
case 16384: printf("... 512MB\n");break;
case 24576: printf("... 768MB\n"); break;
case 32768: printf("... 1GB\n"); break;
case 40960: printf("... 1.2GB\n"); break;
case 49152: printf("... 1.5GB\n"); break;
case 57344: printf("... 1.7GB\n"); break;
case 65532: printf("... 2GB (solaris 2.5.1 limit)\n"); break;
case 73728: printf("... 2.2GB\n"); break;
case 81920: printf("... 2.5GB\n"); break;
case 90112: printf("... 2.7GB\n"); break;
}
}

printf("\nAllocated %d 32KB Chunks\n", chunks);
printf("Total allocated memory is %d MBytes\n", (chunks * CHUNK)/MBYTE);
printf("\n***Press <enter> to free the memory and exit\n");
getchar();

exit(0);
}
</pre>